Chemistry, asked by mathewjustin5887, 1 year ago

Of molecules of sulphur s8 present in 512 gram of solid sulphur .Given atomic mass of s is equals to 32 u .Avogadro no. = 6.022 *10^23 permole

Answers

Answered by akash2376
0

So, in 512gm of solid Sulphur,

S8 has a molecular weight eqaul to 256gm(8x32)

So 2moles of S8 is there in solid Sulphur.

For 2moles,

2 x 6.022 x 10^23

That is equal to,

1.204 \times   {10}^{24} molecules

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