Question

% of Na in sodium peroxide is:

(Mass no. of Na=23, O=16)​

Answer 1

Answer:

Formula of Sodium Peroxide is Na2o3

Molecular mass of Na in Na2O2 = 23*2 = 46 a.m.u

Molecular Mass of Na2O2= (23*2)+(16*2) = 78 a.m.u

Therefore, % Na in Na2O2 =

$100 \times \frac{46}{78 }$

= 58.97%