Question

of one of the zeroes of the cubic polynomial x³+ax²+bx+c is -1, then the product of the other two zeroes is
a) b-a+1
b) b-a-1
c) a-b+1
d) a-b-1​

Answer 1

Answer:

ab= 0

Step-by-step explanation:

→a=α+β−1

→ b=αβ−β−α              →              Property

→ c=−αβ

→Also−1+a−b+c=0

→ 0−b+c=1

→ ∴−α−β+1−αβ+β+α−αβ=1

→ ∴1−2αβ=1

∴αβ=0

thank you