Question

of p.
Class
30-40
40-50
0-10
20-30
10-20
3
2
Frequency
3
4
р
(CBSE 2013]
8. If the mean of the following frequency distribution is 24, find the value​

Answer 1

Answer:

Class Interval Frequency f

i

Mid-Value x

i

f

i

x

i

0−10 3 5 15

10−20 4 15 60

20−30 p 25 25p

30−40 3 35 105

40−50 2 45 90

∑f

i

=12+p ∑f

i

x

i

=270+25p

Mean =

∑f

i

∑f

i

x

i

Mean =24 (given)

⇒24=

(12+p)

(270+25p)

⇒24(12+p)=270+25p

or p=18