of p is * 1(3x + 2)(3x-)=9x?- p then the value 1
Answers
Answer:
Solve it:
Solve it:If the sum of zeroes of the quadratic polynomial 3x
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of K
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of KAnswer
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of KAnswer9
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of KAnswer9In a general quadratic equation of form ax
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of KAnswer9In a general quadratic equation of form ax 2
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of KAnswer9In a general quadratic equation of form ax 2 +bx+c=0, sum of roots are by
Solve it:If the sum of zeroes of the quadratic polynomial 3x 2 −kx+6 is 3 then find the value of KAnswer9In a general quadratic equation of form ax 2 +bx+c=0, sum of roots are by a
In the given quadratic equation, 3x
In the given quadratic equation, 3x 2
In the given quadratic equation, 3x 2 −kx+6=0
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots =
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b =
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k)
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k)
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) =
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒ 3
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒ 3k
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒ 3k
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒ 3k =3
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒ 3k =3⇒
In the given quadratic equation, 3x 2 −kx+6=0Sum of roots = a−b = 3−(−k) = 3k and sum of roots is given 3⇒ 3k =3⇒ k=9
Answer:
3x
2
+px−8=0
Substitute x=2, since 2 is root of equation
⇒ 3(2)
2
+p(2)−8=0
⇒ 12+2p−8=0
⇒ 4+2p=0
∴ p=−2
⇒ 4x
2
−2px+k=0
⇒ 4x
2
−2(−2)x+k=0 [ Since, p=−2 ]
⇒ 4x
2
+4x+k=0
⇒ Here, a=4,b=4,c=k
⇒ It is given that roots are equal.
∴ b
2
−4ac=0
⇒ (4)
2
−4(4)(k)=0
⇒ 16−16k=0
⇒ 16k=16
∴ k=1