of p(y) =y² find the value of p(0) p(1) p(2)
Answers
Answered by
1
⟹ p(y) = y²
⟹ p(0) = 0² = 0
⟹ p(1) = 1² = 1
⟹ p(2) = 2² = 4
Answered by
1
Step-by-step explanation:
P(y)=y^2
P(0)=0^2
=0
P(1)=1^2
=1
P(2)=2^2
=4
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