Question

of radius
Chord AB and CD are at a distance
circle
of 42cm from each other in a
Find the length of
CD pf ABP 36cm
30 cm a​

Answer 1

Answer:

Step-by-step explanation:

Radius = 30 cm

Step-by-step explanation:

Given:

Here, chords AB = 6 cm, CD = 12 cm and AB║CD    

Draw OP⊥ AB. Let it intersect CD at Q and AB at P

∴ AP = PB = 18 cm and CQ = DQ = 24 cm [Since perpendicular draw from the centre of the chord bisects the chord]

Let OD = OB = r

In right Δ OQD,

   [By Pythagoras theorem]

                      (1)

In right ΔOPB,  

            [given distance between the chords, QP = 42 cm ]

      [By Pythagoras theorem]

          (2)

From (1) and (2) we get  

⇒ 576 = 84x + 2088

⇒ 84x = 576 - 2088

⇒ 84 x = -1512

⇒  

⇒ x = - 18

Put x = - 18 in (1), we get

r = 30 cm

Therefore radius = 30 cm.

Answer 2

Answer:

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