of sec A = 25/7, find the value of sin A
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secA= hypotenuse/ base
secA=25/7
hyp=25;base=7
using Pythagoras theorem
hypotenuse^2= perpendicular^2+ base^2
(25)^2= per^2+7^2
625=perp^2+ 49
(perp)^2=576
perp= 24
sinA= perp/ hyp
sinA =24/25
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