Question

of sign changes in
cannot have zero negative roots. So the number of
between number of sign changes in coefficient of P(x)
must be even, we must have either zero or two positi
coefficients is zero, I is a root. Thus we must have no and
the other two roots are imaginary numbers.
EXERCISE 3.6
1. Discuss the maximum possible number of positive and
equation 9x - 4r +4r" - 3x + 2x +x+7r+7x+2=
2. Discuss the maximum possible number of positive and
- 5x+6 and r- 5x+16. Also draw rough sketch oft
Show that the equation r' - 58' +4.r*+2x+10 has a
Determine the number of positive and negative roots of
Find the exact number of real zeros and imaginary of the p
EXERCISE 3.7
se the correct or the most suitable answer from the gi
A zero of +64 is
(1) 0 (2) 4 (3) 4i (4) 4
If f and g are polynomials of degrees m and n resp
and ifh(x)=(fºg)(x). then the degree of his
(2) m+n (3) m
A polynomial equation in x of degree n always has
(1)n distinct roots (2)n real roots (3) n is​

Answer 1

Answer:

Hey mate l am sorry to say but you haven't written a correct question