of sinx=3/5, cosy=-12/15 wherex and y both are in second qudrant find the value of sin(x+y)
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Sin(x+y)= sinX cosY +cosX sinY
3/5*12/15 + 12/15*3/5
0.48+0.48
= 0.96 is the answer
3/5*12/15 + 12/15*3/5
0.48+0.48
= 0.96 is the answer
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