Question

of sum of zeros and product of zeros of p (x) =x²+(k-g)x+(k-1)are equal then find value of k​

Answer 1

p(X)=x²+(k-g)X+(k-1)

sum of zeroes= product of zeroes

-b/a=c/a

-b=c

-(k-g)=k-1

-k+g=k-1

-2k=-(1+g)

k=1+g/2

Answer 2

$\huge\bf{ \underline{ \underline{Answer}}}$

$\rm{Sum\:of\:zeroes\:=\:\frac{-b}{a}}$

$\rm{Sum\:of\:zeroes\:=\:\frac{-(k-g)}{1}\:=\:g-k}$

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$\rm{Product\:of\:zeroes\:=\:\frac{c}{a}}$

$\rm{Product\:of\:zeroes\:=\:\frac{(k-1)}{1}\:=\:k-1}$

A.T.Q

$\rm{k-1\:=\:g-k}$

$\rm{k+k\:=\:g+1}$

$\rm{2k\:=\:g+1 }$

$\rm{k\:=\:\frac{g+1}{2}}$

$\huge\bf{ \underline{ \underline{Thanks}}}$