Question

of tan a =2 evaluate ,sec a ,sin a + tan²a - cosec a​

Answer 1

Answer:

tanA=2

∵, sec²A-tan²A=1

or, sec²A=1+tan²A

or, sec²A=1+4

or, secA=√5

∴, cosA=1/secA=1/√5

Again, sin²A+cos²A=1

or, sin²A=1-cos²A

or, sin²A=1-1/5

or, sin²A=4/5

or, sinA=2/√5

∴, cosecA=1/sinA=√5/2

∴, secA.sinA+tan²A-cosecA

=√5.2/√5+(2)²-√5/2

=2+4-√5/2

=6-√5/2