Of the 1 , a, n, d and Sn, determine the ones that are missing for each of the following arithmetic progressions
(i) a = -2, d= 5, Sn= 568
(ii) l = 8, n= 8, S8= -20
(iii) a= -3030, l= - 1530, n= 5
(iv) d= 2/3 , l= 10, n= 20
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Answer:
i)
Step-by-step explanation:
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Answer:
i)a=−2,d=5,Sn=568
Sn=2n(2a+(n−1)d)=568
⇒2n(−4+(n−1)5)=568
⇒n(5n−9)=1136
⇒5n2−9n−1136=0
⇒n=2×59±81+4×5×1136
=109±151=16 −14.2
n=16
l=a+(n−1)d=−2+15×5+23
ii)l=8,n=8,S8=−20
l=a+(n−1)d⇒a+7d=8
S8=28(a+l)=
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