Question

of the 3 angle of a triangle the second one is one third of the first and the third angle is 26 degree more than the first angle find all the 3 angle of a triangle​

Answer 1

Answer:

Let the first angle =∠A =x

the second angle = ∠B = 1/3x

and the third angle = ∠C = x + 26°

∠A + ∠B + ∠C = 180°

x + 1/3x + x+26° = 180°

7x/3 + 26° = 180°

7x/3 = 180° - 26°

7x/3 = 154°

x = 154° x 3/7

x = 66°

∠A = x= 66°

∠B =1/3 x = 1/3 x 66° = 22°

∠C = x + 26° = 66°+ 26° = 92°