Of the 3 numbers the sum of the first two is 55 sum of the second and third is 65 and sum of the third with thrice of the first is 110 then the third number is
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let 'a' , 'b' and 'c' be the three numbers
According to question,
a + b = 55 -----------(1)
b + c =65-------------(2) and 3a + c =110------------(3)
on solving eq(1) and eq(2), we get
a - c = -10-------------(4)
on solving eq(3) and eq(4), we get
a = 25
substituting a=25 in eq(4), we get c=35
substituting c=35 in eq(1), we get b=30
∴ a=25, b=30, c=35
∴the third number (c) = 35
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