of the 4 number whose avarage is 60. The first is 1/4 th of the sum of last three find the 1st number..
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Let the first number be x
According to the question
Sum of four numbers =x+4x=5x
As first number x is one fourth of the sum of the last three 4x
So,
4
5x
=60
5x=240
x=48
Therefore the first number is 48.
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