Of the 4 numbers whose average is 91, the first number is 3/10times the sum of other 3. the first number is
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let numbers are x1,x2,x3 and x4
(x1+x2+x3+x4)=91×4......(1)
3/10(x2+x3+x4)=x1
(x2+x3+x4)=10x1/3.......(2)
put eqn 2 in eqn 1
10x1/3+x1=91×/4
x1=84
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