Math, asked by ranjeet129, 11 months ago

Of the 400 persons, who were interviewed for a post at an MNC, 200 owned a four-wheeler, 140 owned a debit card and 280 owned a wrist watch. 80 of them owned both, a four-wheeler and a debit card, 60 owned both, a debit card and a wrist watch and 120 owned both, a four-wheeler and wrist watch and 10 owned all three. How many candidates had none of the three objects mentioned?​

Answers

Answered by Anonymous
7

Answer:

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your answer is here !

Step-by-step explanation:

=> Number of persons who owned none of the three = Total number of persons - number of persons who owned at least one of three devices.

=> The total number of persons = 400.

Number of candidates who owned at least 1 of the 3 objects = A ∪ B ∪ C,

=> where A is the set of people who owned a four wheeler,

=> B is the set of those who owned a debit card and C is the set of those who owned a wrist watch.

=> As A∪B∪C = A + B + C - {A n B + B n C + C n A} + A n B n C.

=> So, A∪B∪C = 200 + 140 + 280 - {80 + 60 + 120} + 20

=] Or A∪B∪C = 380.

=> 380 candidates who attended the interview had at least one of the three gadgets,

=> so 400 - 380 = 20 candidates had none of three objects.

=> follow me !

Answered by rithvik301
0

Number of persons who owned none of the three =

Total number of persons - number of persons who owned at least one of three devices.

The number of persons = 400.

Number of candidates who owned at least 1 of the 3 objects = A / B / C,

where A is the set of people who owned a four wheeler,

B is the set of those who owned a debit card

C is the set of those who owned a wrist watch.

=> As A/B/C = A + B + C - {A - B + B - C + C -A} + A - B - C.

=> So, A/B/C = 200 + 140 + 280 - {80 + 60 + 120} + 20

=] Or A/B/C = 380.

380 candidates who attended the interview had at least one of the three gadgets,

400 - 380 = 20 candidates had none of these objects.

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