Question

of the A.P.
12 Find the 19th term
7, 13, 19, 25,​

Answer 1

Solution. The given sequence is 7, 13, 19, 25,.... Hence, the 19th term of the progression is 115.

a = 7 d = 13 - 7 = 6 n = 19 using formula an = a + (n - 1)d putting the values we get, an = 7 + (19 - 1)6 an = 7 + 18 × 6 an = 7 + 108 an = 115 So,

Find the first term and common difference for each of the A.P. (1) 5, 1 ... The given sequence is –12, –5, 2, 9, 16, 23, 30,. ... The given sequence is 7, 13, 19, 25,.

Answer 2

Step-by-step explanation:

Ap is 7,13,19,25

a=7

d=13-7

=6

tn=a+(n-1) d

t19=7+(19-1)6

=7+18×6

=115

19th term is 115

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