Math, asked by viki5440, 11 months ago

Of the adults population in a certain village 42% of men and 24% of women are married assuming that no man marries more than one womenand vice versa the percentage of total population

Answers

Answered by sanjeevk28012
1

Given :

The percentage of married men in village = 42%

The percentage of married women in village = 24%

To Find :

The percentage of total percentage

Solution :

Let no of men in village  = x

and total population of village = 100

Then Total number of women in village = Total population - number of men

                                                                  = 100 - x

Now,

number of married man =  42 % of total men

                                        = \dfrac{42}{100} × x

                                       = 0.42 x

number of married women = 24 % of total women

                                             = \dfrac{24}{100} ×  (100-x)

                                            = 0.24 ( 100 - x )

∵   No man marries more than one women and vice versa

So,   0.42 x = 0.24 ( 100 - x )

Ie.  0.42 x = 24 - 0.24 x

Or,   0.42 x + 0.24 x =  24              

Or,  0.66 x = 24

∴             x = \dfrac{2400}{66}

So, number of men in village = x = \dfrac{2400}{66}

So, Number of married men = 0.42 × \dfrac{2400}{66}

                                              = \dfrac{168}{11}

And, number of women in  village = 100 - x

                                                         = 100 - \dfrac{2400}{66}

                                                         = \dfrac{4200}{66}

So, number of married women = 0.24  × \dfrac{4200}{66}

                                                    = \dfrac{168}{11}

So, Total married population =  \dfrac{168}{11} + \dfrac{168}{11}

                                                = \dfrac{336}{11}

%age of total married population = 30.54 %

Hence, The percentage of married population is village is 30.54%   Answer

Answered by shobhitsharma098
1

Step-by-step explanation:

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