Of the candidates who sat for an international mathematics examination, 18% of the candidates obtained
grade A, 38% obtained grade B and the rest obtained grade C. Given that 77 candidates obtained grade C,
find the total number of candidates who sat for the examination.
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Answer:
total% = 100%
grade A=18%
grade B=38%
grade C= 100-(18+38)
grade C=44%.
therefore,
44% of T= 77
11/25 of T = 77
T= 77 ÷11/25
T=77×25/11
T=175
isehrishnadeem:
thanks for helping!
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