Question

of the car is 1 ms
and the distance covered is 37.5 m.
ILIUI
Example 8.7 The brakes applied to a car
produce an acceleration of 6 m s2 in
the opposite direction to the motion. If
the car takes 2 s to stop after the
application of brakes, calculate the
distance it travels during ​

Answer 1

Answer:

Distance is 12 m

Explanation:

Given ,

Acceleration of the car= - 6 m/s²( since in the question it is mentioned that the direction is opposite to the direction of motion.)

Time(t)= 2 seconds

Final velocity (v)= 0 m/s ( since the car finally stops)

Let the initial velocity be u.

Hence,

Acceleration= change in velocity/ time

Or, a= v-u/t

Or, -6= 0-u/2

Or, -u= -12

Or, u= 12 m/s

Now, by second equation of motion,

S= ut+at²/2

Or, S= 12*2+(-6)*2*2/2

Or, S= 24-12

Or, S= 12 m

Answer : distance is 12 m