Question

Of the coordinate of P is m then d(O,P)=...(O is the origin)worng answers will be reported..no spamming...only right answers..​

Answer 1

Answer:

The coordinates of the points O and P are (0,0,0) and (1,2,−3) respectively.

Therefore, the direction ratios of OP are

(1−0)=1,(2−0)=2 and (−3−0)=−3

Thus the direction ratios of normal are 1,2 and −3 and the point P is (1,2,−3).

Thus, the equation of the required plane is

1(x−1)+2(y−2)−3(z+3)=0

⇒ x+2y−3z−14=0

Answer 2

Answer:

The coordinates of the points O and P are ( 0,0,0 ) and ( 1 , 2 , -3 ) respectively.

Therefore, the direction ratios of OP are

( 1 - 0 ) = 1,(2-0)=2 and (-3-0) = -3

Thus the direction ratios of normal are 1,2 and -3 and the points P is ( 1,2,-3 ) .

Thus , the direction ratios of normal are 1, 2 and - 3 and the equation of the required plane is

1 (x- 1 ) + 2(y -2) - 3(z+3 = 0