of the coordinates of two points are P (-3,4) and Q f. 4, 8) then find the value of
abscissa of P.) - (ordinate of 9).
Why
Answers
Answered by
7
Answer:
Abscissa of P is -3
Ordinate of Q is 8. ( u have given wrong as ordinate of 9, just change it Ordinate of Q)
Given : (Abscissa of p) - (Ordinate of Q)
= (-3)-(8)
= -11
:) Your answer is -11
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@Niranjana1906
Answered by
0
Given P(−3,3),Q(−3,5)
Abscissa of P=−3
Abscissa of Q=−3
Now,
Abscissa of P − Abscissa of Q
=−3−(−3)=0
Hence, this is the answer.
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