of the diagonals of rhombus of the side are 15cm are in ratio 3:4, find the area of rhombus
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Solution :-
The side of rhombus = 15 cm
Ratio of two diagonals = 3 : 4
The rhombus is formed of 4 right angled triangles. Our basic Pythagoras Triplet is 3 : 4 : 5
Since, the hypotenuse in this case is 15 cm (that is 5 × 3 = 15), the other two sides of the right angled triangle will be 9 (3 × 3 = 9) and 12 (4 × 3 = 12).
9 : 12 : 15 is also a Pythagoras Triplet.
These sides of the right triangle are half the entire diagonal, so the two diagonals are -
9*2 = 18 cm and
12*2 = 24 cm
So, the two diagonals are 18 cm and 24 cm respectively..
Now,
Area of the given rhombus = (Diagonal 1 × Diagonal 2)/2
⇒ (18*24)/2
⇒ 432/2
= 216 sq cm
Answer.
The side of rhombus = 15 cm
Ratio of two diagonals = 3 : 4
The rhombus is formed of 4 right angled triangles. Our basic Pythagoras Triplet is 3 : 4 : 5
Since, the hypotenuse in this case is 15 cm (that is 5 × 3 = 15), the other two sides of the right angled triangle will be 9 (3 × 3 = 9) and 12 (4 × 3 = 12).
9 : 12 : 15 is also a Pythagoras Triplet.
These sides of the right triangle are half the entire diagonal, so the two diagonals are -
9*2 = 18 cm and
12*2 = 24 cm
So, the two diagonals are 18 cm and 24 cm respectively..
Now,
Area of the given rhombus = (Diagonal 1 × Diagonal 2)/2
⇒ (18*24)/2
⇒ 432/2
= 216 sq cm
Answer.
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