Question

of the digits of a two-digit number is 9. When we interchange the digits, it is
the resulting ney number is greater than the original number by 27. What
is the number? ???​

Answer 1

let the digits are X(one place) and y(second place)

now ...X+y=9

=>y=9-x

now the number is =10y+X

the reverse number is =10X+y

now ....

$10x + y = 10y + x + 27 \\ = > 9x = 9y + 27 \\ = > x - y = 3 \\ = > x - 9 + x = 3 \\ = > 2x = 12 \\ = > x = \frac{12}{2} = 6 \: \: \\ and \\ y = 3$

therefore the original number is =10(3)+6

=36