Question

of the distance s meters traversed by a particle in t seconds is given by s=t^3 - 3t^2 then the velocit of the particle when the acceleration is zero

Answer 1

Answer:

$velocity=-3\:m/s$

Step-by-step explanation:

Concept used:

If the distance time equation of a moving particle is s= f(t), then

$velocity=\frac{ds}{dt}$

$Acceleration=\frac{d^2s}{dt^2}$

Given:

$s=t^3-3t^2$

$velocity=\frac{ds}{dt}$

$velocity=3t^2-6t$

$Acceleration=\frac{d^2s}{dt^2}$

$Acceleration=6t-6$

when acceleration is zero,

$6t-6=0$

$6t=6$

$t=1$

At t=1,

$velocity=3(1)^2-6(1)$

$velocity=3-6$

$velocity=-3\:m/s$