Question

of the following questions
. In a AABC, if 32A = 42B = 62C then A:B:C = ?​

Answer 1

Answer:

16:21:31

Step-by-step explanation:

A=32

B=42

C=62

A:B:C

32:42:62

16:21:31

Answer 2

Answer:

let's assume, 32A=42B=62C=K [where k≠0]

Then, A=K/32,, B=K/42 ,, C=K/62

Hance, A:B:C=K/32 : K/42 : K/62

=1/16 : 1/21 : 1/31 = 10416/16 : 10416/21 : 10416/31

= 21×31 : 31 ×16 : 16×21

= 651 : 496 : 336

Hope it's help....