Question

Of the four numbers, whose average is 60, the first is one-fourth of the sum of the last
three. The first number is :
(a) 15
(b) 45
(c) 48
(d) 60.25​

Answer 1

Answer:

15 is ur answer for this question

Step-by-step explanation:

mark me as a brainlist

Answer 2

Answer:

Option (c), 48 is correct answer.

Step-by-step explanation:

Let the four number be a, b, c and b.

Given their average is 60.

$\therefore \cfrac{a+b+c+d}{4}= 60$

$\Rightarrow a+b+c+d = 240$      ...(1)

Also given that first is one-fourth of the sum of the last three.

$\therefore a = \cfrac{1}{4} (b + c+d)$

$\Rightarrow 4a = b + c + d$

Now, putting value of b + c + d in Eqn. (1), we get

$a + 4a = 240$

$\Rightarrow 5a = 240$

$\Rightarrow a = \cfrac{240}{5}$

$\Rightarrow a = 48$

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