Question

of the members of three athletic teams in a certain school,21 ij are in basket ball team,26 in a hockey team and 29 in the football team.14 play hockey and basketball,15 play hockey and football,12 play football and basket ball and 8 play all the three games.how many members are there in all​

Answer 1

Answer:

Let B, H, F denote the sets of members who are in the basket hall team, hockey team and football team respectively.

Given n(B)=21,n(H)=26,n(F)=29. n(H∩B)=14,n(H∩F)=15, n(F∩B)=12 and n(B∩H∩F)=8.

We have to find n(B∪H∪F).

n(B∪H∪F)=n(B)+n(H)n(F) −n(B∩H)−n(H∩F)−n(F∩B)+n(B∩H∩F).

Answer 2

Answer:

8 members plays all three games

6 excluding middle 8 plays hockey and basketball

12 only plays hockey  

7 only plays basketball  

21 only plays football  

so total members = 8 + 6 + 12 + 7 + 21  

= 54

Step-by-step explanation:

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