Question

of the passenger train, find the average speed of the two lang.
Sum of the areas of two squares is 468 m². If the difference of their perimeters is 24 m,
find the sides of the two squares.​

Answer 1

Step-by-step explanation:

Let the length of the side of the first square be x .

Perimeter of first square = 4x

Let the length of the side of the second square be y m.

Perimeter of second square = 4y

Now, 4y−4x=24

or, y−x=6 (Dividing both sides by 4)

or, y=x+6

Now, area of second square = y 2=(x+6)2

= x2 +12x+36

Area of first square = x2

Now, x2+12x+36+x2=468 (Sum of areas)

or, 2x2+12x+36=468

or, x2 +6 x +18=234 (Dividing both sides by 2)

or, x2 +6x+18−234=0

or, x2 +6x−216=0

or, (x+18)(x−12)=0 (Factoring the equation)

or, x=−18,12

Since x cannot be negative,therefore,

x=12m

Therefore, x + 6 = 18m

So the sides are 18m and 12m respectively.

Hope that helps.