Question

of
The perpendiculad drawn brom the cent?
a circle toth its chord bis-
ects the​

Answer 1

Answer:

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Step-by-step explanation:

By theorem, the perpendicular from the center of a circle to a chord bisects the chord. So, C'C bisects AB. Since CC' ⊥ AB and line segment joining the centers of two circles bisects the common chord. Therefore, C' is the mid-point of AB.

Answer 2

Answer:

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