Question

of the radius of cylinder is doubled and height id halved then the ratio of the volume of original and new cylinder will be​

Answer 1

answer:

in case of an original cylinder:

volume of an original cylinder =

$\pi \: r {}^{2} h$

r = radius

h = height

in case of a new cylinder:

radius = 2r

height = h / 2

volume of the new cylinder will be

$\pi4r {}^{2} { \frac{h}{2} }$

$\pi2r {}^{2} {h}$

ratio of the original and new cylinder will be:

$\pi \: r {}^{2} h \: \div \: \ \: \pi2r { \: }^{2} {h}$

$\frac{1}{2}$

so, the radio will be: 1:2