Question

of the roots of the quadratic equation ( a- b) x2 + (b- c) x+(c-a) are equal then prove that 2a= b+c​

Answer 1

Answer:

Step-by-step explanation:

a=(a-b)

b=b-c

c=c-a

D=b^2-4ac

(b-c)^2-4(a-b)(c-a)=0

b^2+c^2-2bc-4(ac-a^2-bc+ab)

b^2+c^2-2bc -4ac+4a^2+4bc-4ab=0

4a^2+b^2+c^2+2bc-4ab-4ac=0

(2a-b-c)2=0  

i.e. 2a-b-c =0

2a= b+c