Of the three angles of a triangle, first angle is thrice the second angle and the second angle is six times the third angle. Find all the angles of the triangle.
Answers
Answered by
38
Let the third angle be 'x'
So,the second angle =6x
And the first angle =18x
Now,
x+6x+18x=180°
=>25x=180
=>x=7.2°
•
• • first angle =129.6°
Second angle = 43.2°
Third angle = 7.2°
So,the second angle =6x
And the first angle =18x
Now,
x+6x+18x=180°
=>25x=180
=>x=7.2°
•
• • first angle =129.6°
Second angle = 43.2°
Third angle = 7.2°
Answered by
18
Sum of angles in a triangle is 180°
SO LET each angle represent x
1st angle=18x
2nd angle=6x
3rd angle=x
18X+6x+x=180°
25x=180°
Divide through by 25
X=7.2
So the 1st angle=18x=18*7.2=129.6
2nd angle=6x=6*7.2=43.2
3rd angle=x=7.2
Hope it helps
SO LET each angle represent x
1st angle=18x
2nd angle=6x
3rd angle=x
18X+6x+x=180°
25x=180°
Divide through by 25
X=7.2
So the 1st angle=18x=18*7.2=129.6
2nd angle=6x=6*7.2=43.2
3rd angle=x=7.2
Hope it helps
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