Question

of the three angles of a triangle, is twice the smallest, third angle is 90 degree find the angles​

Answer 1

Answer:

Consider ∠C is the smallest angle among ∠ABC

According to the question

We can write it as

∠A=2∠C and ∠B=3∠C

We know that the sum of all the angles in a triangle is 180∘.

So we can write it as

∠A+∠B+∠C=180∘

By substituting the values

2∠C+3∠C+∠C=180∘

By addition

6∠C=180∘

By division

∠C=180/6

∠C=30∘

Now by substituting the value of ∠C we get

∠A=2∠C=2(30∘)=60∘

∠B=3∠C=3(30∘)=90∘

Therefore, ∠A=60∘,∠B=90∘ and ∠C=30∘.

Step-by-step explanation:

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Answer 2

Answer:

2x+x+90=180

3x+90=180

3x=90=30

so <1=30

<2=60

<3=90

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