Of the three angles of a triangle of a triangle one is twice the smallest and another is three times smallest find the angles
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Let's take one of the angles as x, which is the smallest angle.
The second angle = 2 × x = 2x
The third angle = 3 × x = 3x
Sum of all the angles of a triangle = 180°
Therefore,
3x + 2x + x = 180°
=> 6x = 180°
=> x = 180° ÷ 6
=> x = 30°
Thus, 2x = 2 × 30° = 60°
3x = 3 × 30° = 90°
So, the three angles of the triangle are 30°, 60° and 90°.
The second angle = 2 × x = 2x
The third angle = 3 × x = 3x
Sum of all the angles of a triangle = 180°
Therefore,
3x + 2x + x = 180°
=> 6x = 180°
=> x = 180° ÷ 6
=> x = 30°
Thus, 2x = 2 × 30° = 60°
3x = 3 × 30° = 90°
So, the three angles of the triangle are 30°, 60° and 90°.
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