Question

of the three angles of a triangle , one is half the greatest and thrice the smallest . find the angles​

Answer 1

Step-by-step explanation:

let the angle be x

largest is 2x

smallest = x/3

..

x+2x+x/3 =180

3x+6x+x / 3 =180

10x=540

x=54 one angle

largest = 2x= 2*54=108

smallest = x/3 = 18

...

CHECK

54+18+108=180

Answer 2

Answer:

18° , 54° , 108°

Step-by-step explanation:

let the one angle which is not smallest nor greatest be 'x'.

x = 3 * smallest angle

smallest angle = 1/3 of x

                         =$\frac 1 3$ x

x= $\frac{1}{2}$ of greatest

greatest angle = 2 * x

                        = 2x

let us find the value of x ,

sum of angles of the triangle = 180 degree

smallest angle + x + greatest = 180 degree

$\frac1 3$ x + x + 2x = 180°

1x + 3x + 3*2x = 180°

        3

1x + 3x+ 6x = 180° * 3

10x = 540°

x = 540° / 10

x = 54°

now we got the value of x ...............

let us find smallest angle .........

smallest = 1/3 of x

(putting the value of x)= 1/3 of 54°

                                     = $\frac{1}{3}$  of 54°

                                     = 18°

now let us find the greatest angle -

greatest = 2x

              = 2 * 54°

              =  108°

Answer - Angles of triangle are  18° , 54° , 108°............

verify - 18° + 54° + 108° = 180°

HOPE IT HELPS.............

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