Question

Of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest. Find the angles. ( Don't spam) ​

Answer 1

Answer:

The sum of the right angled triangle is 180 degree. One of the angles of a right angled triangle is always 90 degree.

So we need to find the other two angles.

Trial 1: If 90/2= 45 is the smallest angle,then the other angle should be 45×3 = 135. That isn't possible as the sum of all the angles adds up to 180.

Trial 2: If 90/3=30 is the smallest angle, then the other angle should be 30×2=60.

Sum of all angles= 60+30+90=180.

This holds true.

Hence the smallest angle is 30 degree. Hence we can also say it is a right angled triangle as it has one angle twice the smallest and another thrice the smallest

Answer 2

Answer Is:-

Consider ∠C is the smallest angle among ∠ABC.

According to the question,

We can write it as,

∠A=2∠C and ∠B=3∠C

We know that the sum of all the angles in a triangle is 180∘

.

So we can write it as,

∠A+∠B+∠C=180∘

By substituting the values,

2∠C+3∠C+∠C=180∘

By addition,

6∠C=180∘

By division,

∠C=180/6

∠C=30∘

Now by substituting the value of ∠C we get,

∠A=2∠C=2(30∘)=60∘

∠B=3∠C=3(30∘)=90∘

Therefore, ∠A=60∘,∠B=90∘ and ∠C=30∘.

Hope it helps you dear.......xD