Question

of the three angles of a triangle, one is twice the smallest and another one is thrice the smallest. find the angles.

Answer 1

let the 3 angles be a , b and c
now let a be the smallest angle
A.T.Q.,
b=2.a and c= 3.a
and a + b + c =180° ( sum of angles of a triangle)
putting the value of a,b n c
a +2a+3a =180°
6a = 180°
a= 30°
so, angle a = 30°
b = 2×30= 60 °
c= 3×30° = 90°
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Answer 2

2x + 3x + angle c= 180°
=5x + angle c = 180°
= angle c = 180°÷5=36° answer