of the three angles of a triangle one is twice the smallest and another is three times the smallest find the largest angle
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let the first angle be A
the 2nd angle be B
abd the 3rd angle be C
According to question,
A = 2C
B = 3C
A + B + C = 180 ( ANGLE SUM PROPERTY)
2C + 3C + C = 180
6C = 180
C = 30DEGREE
NOW ,
A = 2C
A = 60DEGREE
B = 3C
B = 90DEGREE
AS = 3rd angle = largest angle = B = 90degree
hope my answer will help u
pls mark my answer as brainliest answer
the 2nd angle be B
abd the 3rd angle be C
According to question,
A = 2C
B = 3C
A + B + C = 180 ( ANGLE SUM PROPERTY)
2C + 3C + C = 180
6C = 180
C = 30DEGREE
NOW ,
A = 2C
A = 60DEGREE
B = 3C
B = 90DEGREE
AS = 3rd angle = largest angle = B = 90degree
hope my answer will help u
pls mark my answer as brainliest answer
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