Question

of the three angles of a triangle the second is one third the first and the third is 26 degree more than the first find the measure of all the angles

Answer 1

Let the first angle =∠A =x 
 the second angle = ∠B = 1/3x
and the third angle = ∠C = x + 26°
 ∠A + ∠B + ∠C = 180°
  x + 1/3x + x+26° = 180°
 7x/3 + 26° = 180°
  7x/3 = 180° - 26°
   7x/3 = 154°
  x = 154° x 3/7
 x = 66°
∠A = x= 66°
∠B =1/3 x = 1/3 x 66° = 22°
∠C = x + 26° = 66°+ 26° = 92°

Answer 2

Answer:

Step-by-step explanation:

Let the three angles be x, x/3,X+26°

A/Q

x+x/3+X+26° =180°

x+x/3+x=(180-26)°

(3x+x+3x)/3=154°

7x/3=154°

x=(154*3)/7

x=66°

Hence the angles are 66°,22°,92°