Question

of the three angles of traingle one of the thrice the smallest and another is six times the smallest find the value of smallest angles and other angles​

Answer 1

Answer:

18°, 54°, 108°

Step-by-step explanation:

let the smallest angle be 'k'

2nd largest angle is 3k

largest angle is 6k

Thus,

k+3k+6k = 180 (ASP of triangle)

10k = 180

k=180/10

k= 18°

=> 3k= 54°

& 6k= 108°

Answer 2

Consider ∠C is the smallest angle

among ∠ABC

According to the question

We can write it as

∠A = 2 ∠C and ∠B = 3 ∠C

We know that the sum of all the angles in a triangle is 180o. So we can write it as

∠A + ∠B + ∠C = 180°

By substituting the values 2 ∠C + 3 ∠C + ∠C = 180°

By addition 6∠C = 180

°By division ∠C = 180/6 ∠C = 30°

Now by substituting the value of ∠C we get

∠A = 2 ∠C = 2 (30°) = 60°∠B = 3 ∠C = 3 (30°) = 90°Therefore, ∠A = 60o, ∠B = 90o and ∠C = 30°

Hope it's Helpful to you (✿ ♡‿♡)