Question

of the three angles of triangle one is twice the smallest and another is three times the smallest find the angles

Answer 1

Define x:

Let the smallest angle = x

2nd angle =2x

3rd angle = 3x

Solve x:

Sum of angles in a triangle is 180

x + 2x + 3x = 180

6x = 180

x = 30

Find the angles:

smallest angle = x = 30º

2nd angle = 2x = 2(30) = 60º

3rd angle = 3x = 3(30) = 90º

Answer: The angles are 30º, 60º and 90º

Answer 2

Let smallest angle be x
A.T.Q x+2×+3x=180
6x=180
x=30
so smallest angle is 30 second angle 60 and third angle is 90.