Question

Of the three consecutive numbers ,five times the smallest number is 9 more than four times the greatest number ,find the number .
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Answer 1

Answer:

$\huge{Hope\;it\;helps\;u}$

Step-by-step explanation:

Let consecutive Number= x , x + 1 , x + 2

Greatest is = x + 2

Smallest = x

Middle = x + 1

5x = 4 (x+2) + 9

5x = 4x + 8 + 9

5x - 4x = 8 + 9

x = 17

Smallest = 17

Now consecutive numbers = 17 , 18 , 19

Answer 2

Answer:

Let consecutive Number= x , x + 1 , x + 2

Greatest is = x + 2

Smallest = x

Middle = x + 1

5x = 4 (x+2) + 9

5x = 4x + 8 + 9

5x - 4x = 8 + 9

x = 17

Smallest = 17

Now consecutive numbers = 17 , 18 , 19

Answer 3

Answer:

Let consecutive Number= x , x + 1 , x + 2

Greatest is = x + 2

Smallest = x

Middle = x + 1

5x = 4 (x+2) + 9

5x = 4x + 8 + 9

5x - 4x = 8 + 9

x = 17

Smallest = 17

Now consecutive numbers = 17 , 18 , 19

Answer 4

Answer:

Let consecutive Number= x , x + 1 , x + 2

Greatest is = x + 2

Smallest = x

Middle = x + 1

5x = 4 (x+2) + 9

5x = 4x + 8 + 9

5x - 4x = 8 + 9

x = 17

Smallest = 17

Now consecutive numbers = 17 , 18 , 19

Answer 5

Answer:

Let consecutive Number= x , x + 1 , x + 2

Greatest is = x + 2

Smallest = x

Middle = x + 1

5x = 4 (x+2) + 9

5x = 4x + 8 + 9

5x - 4x = 8 + 9

x = 17

Smallest = 17

Now consecutive numbers = 17 , 18 , 19