Question

Of the three numbers, second is twice the first
and is also thrice the third. If the
average
of three
numbers be 44. find the smallest number.​

Answer 1

hope it helps... thanks

Answer 2

$\huge{\underline{\pink{\tt{Given,}}}}$

• The Three Number of Average is 44.
• The Second Number is twice the First and also thrice the third Number .

$\huge{\underline{\pink{\tt{To \ Find,}}}}$

• The Smallest Number

$\huge{\underline{\pink{\tt{Solution :}}}}$

$\implies$ Suppose the First Number be $\red{\sf{a}}$

So, Second Number will be $\red{\sf{2b}}$

And, Third Number will be $\red{\sf{2a/3 }}$

$\star{\underline{\sf{\purple{According\:to\:the\:given\:Condition:}}}}$

• The average of the three numbers is 44, therefore the sum of these three numbers would be $\boxed{\sf{44 \times 3 = 132}}$.

Now, According to the Question :

• The Average of the three Number is 44

$\longrightarrow \red{\tt{\dfrac{\:Sum\:of\:All\:Observation}{Number\:of\:Observation }}}$

$\longrightarrow \sf{\dfrac{\dfrac{a + 2a + 2a}{3}}{3}= 132}$

$\longrightarrow \sf{\dfrac{3a + 6a + 2a}{3} = 132}$

$\longrightarrow \sf{\dfrac{11a}{3} = 132}$

$\longrightarrow \sf{11a = 396}$

$\longrightarrow \sf{a = \dfrac{396}{11}}$

$\longrightarrow \boxed{\tt{a = 36}}$

Therefore, The Numbers are :

• $\red{\sf{First\:Number}}$ (a) = 36
• $\red{\sf{Second\:Number}}$ (2a)= 36 ×2 = 72
• $\red{\sf{Third\:Number}}$ (2a/3)= 72/3 = 24

$\boxed{\sf{\pink{Smallest\:Number = Third\:Number = 24}}}}$

$\rule{200}2$