Question

of the three numbers second number is twice the first number and is also thrice the third number, if the average of three number is 44. find the largest number. plz give method also ...

Answer 1

Let the first number is x .

According to the question,

2nd number = 2x

but given

2nd number is thrice the 3rd number.

3rd number = 2x ÷ 3 = 2x/3

Now, we have given its average is 44

$average = \frac{sum \: of \: given \: number}{total \: number} \\ \\ \implies44 = \frac{x + 2x + \frac{2x}{3} }{3} \\ \\ \implies 132 = \frac{3x + 6x + 2x}{3} \\ \\ \implies 132 \times 3 = 11x \\ \\ \implies x = 12 \times 3 \\ \\ \implies \boxed {x = 36}$

VERIFICATION :-

Putting value of x in LHS ;

$\frac{36 + 72 + 24}{3} = 44$

= RHS

Hence, the 3 numbers are 24,36 and 72.

The largest number is 72.