Question

of the three numbers the first is 60% more than the third and 20% more than the third by how much percentage the second less than the third?​

Answer 1

Answer:

Let the number is = x

65% of the number is 65x/100

36% of the number is 36x/100

Difference is 29x/100

Therefore 29x/100 = 58

x = (58×100) /29 = 200

23% of the number = (23/100) ×200=46

Answer 2

Answer:

46 is ur right answer

hope it helps