Question

Of the three numbers the first is twice the second and is half the third if the average of three numbers is 56 then three numbers in order are..pls any one can answer this question with explanations. Unnecessary answer will be reported...​

Answer 1

Step-by-step explanation:

$\sf\large\underline\purple{Let:-}$

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$\displaystyle \sf \bigstar \: \: { \bold{let \: second \: number \: be \: x}} \\ \\ \displaystyle \sf \bigstar \: \: { \bold{ first \: number \: = 2x}} \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \bigstar \: \: { \bold{third \: number \: \: = \frac{x}{2} }} \: \: \: \: \: \: \:$

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$\sf\large\underline\purple{Formula:-}$

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$\displaystyle \sf \bigstar \: \: \: \boxed{ \underline{ \boxed{ \bold{ \frac{total \: sum \: of \: all \: numbers}{number \: of \: items \: in \: the \: set} }}}}$

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$\sf\large\underline\purple{Formula:-}$

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$\displaystyle \sf \longrightarrow \: \frac{ 2x + x + \frac{x}{2} }{3} = 56 \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow4x + 2x + x = 56 \times 6 \\ \\ \displaystyle \sf \longrightarrow7x \: = 336 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \displaystyle \sf \longrightarrow \: \small{ \rm { \green{ \boxed{x \: = 48}}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$