Question

Of the three numbers, the first is twice the second and is half the third. If the

average of three numbers is 56, the three numbers in order are​

Answer 1

Answer:

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Step-by-step explanation:

bsbsbshsnjsjsks

Answer 2

Answer:

Let the 2nd number be x.

Since the 1st number is twice the 2nd, it is 2x.

Since the 1st number is half of the 3rd, i.e., the 3rd number is twice the 1st, the 3rd number is 4x.

The average of the three numbers is 56, so

\begin{gathered} \frac{2x + x + 4x}{3} = 56 \\ 7x = 56 \times 3 \\ x = \frac{56 \times 3}{7} \\ x = 8 \times 3 \\ x = 24\end{gathered}

3

2x+x+4x

=56

7x=56×3

x=

7

56×3

x=8×3

x=24

Now the difference between the 1st and the 3rd numbers is

\begin{gathered}4x - 2x \\ = 2x \\ = 2 \times 24 \\ = 48\end{gathered}

4x−2x

=2x

=2×24

=48

Step-by-step explanation:

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